MySQL Query In PHP to get a field out of a table.. |
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MySQL Query In PHP to get a field out of a table.. |
Nov 3 2009, 04:37 PM
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Advanced Member ![]() ![]() ![]() Group: Members Posts: 7,885 Joined: 23-November 08 Member No.: 6,521 |
Hi there,
I am in need of desperate help. I am using a PHP calendar script. I am trying to display an image for each date in the calendar. See my attempt here: http://proudcabaret.com/calendar/cal...h=11&year=2009 Its not quite right. The image field is called "promoimage" which is part of every record in the table of events. This is a URL. My code is as follows: Code: <? include('admin/dbconn.php'); include('functions/functions.php'); include('header.php'); $query= 'SELECT * FROM calendar_event ORDER BY day'; $result=mysql_query($query); $num=mysql_numrows($result); $type = CAL_GREGORIAN; $month = $_GET['month']; if(!$_GET['month']) { $month = date('n'); } // Month ID, 1 through to 12. $year = $_GET['year']; if(!$_GET['month']) { $year = date('Y'); } // Year in 4 digit 2009 format. $today = date('Y/n/d'); $day_count = cal_days_in_month($type, $month, $year); // Get the amount of days in the chosen month to give to our function. echo "<div id='calendar'>"; echo "<div id='calendar_wrap'>"; // Function for year change. // $last_month = $month - 1; $next_month = $month + 1; $last_year = $year - 1; $next_year = $year + 1; if($month == 12) { $change_year = $year; $change_month = $last_month; } elseif($month == 1) { $change_year = $last_year; $change_month = '12'; } else { $change_year = $year; $change_month = $last_month; } if($month == 1) { $change_year_next = $year; $change_month_next = $next_month; } elseif($month == 12) { $change_year_next = $next_year; $change_month_next = '1'; } else { $change_year_next = $year; $change_month_next = $next_month; } // Do NOT edit the above. // echo "<div class='title_bar'>"; echo "<a href='/calendar/calendar.php?month=". $change_month ."&year=". $change_year ."'><div class='previous'></div></a>"; echo "<a href='/calendar/calendar.php?month=". $change_month_next ."&year=". $change_year_next ."'><div class='next'></div></a>"; echo "<h2 class='month'>" . date('F', mktime(0,0,0,$month,1)) . " " . $year . "</h2>"; echo "</div>"; for($i=1; $i<= $day_count AND $num; $i++) { // Start of for $i $date = $year.'/'.$month.'/'.$i; $get_name = date('l', strtotime($date)); $month_name = date('F', strtotime($date)); $day_name = substr($get_name, 0, 3); // Trim day name to 3 chars $day_st = date('S', strtotime($date)); $count = count_events($i, $month,$year); echo "<a href='day_view.php?day=$i&month=$month&year=$year' title='$i $month_name' rel='day_view'>"; echo "<div class='calwrap'>"; // wrapper echo "<div class='cal_day'>"; // Calendar Day echo "<div class='day_heading'>" . $day_name . "</div>"; if($today == $date) { echo "<div class='day_number today'>" . $i . $day_st ."</div>"; } else { echo "<div class='day_number'>" . $i . $day_st ."</div>"; } $promoimage=mysql_result($result, $i, "promoimage"); if($count >= 1) { if (empty($promoimage)) { echo "<span class='event'>Event</span>"; } else { echo "<span class='event'><img src='". $promoimage ."'></span>"; } } echo "</div>"; echo "</div>"; echo "</a>"; } // EOF for $i echo "</div>"; ?> <script type="text/javascript"> $(document).ready(function(){ $("a[rel='day_view']").colorbox({width:"500px", height:"450px", iframe:true}); }); </script> If anyone can help, id be eternally greatful. I think my coding is wrong. |
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Lo-Fi Version | Time is now: 21st November 2009 - 04:30 PM |